Calculate the mass in grams of 8.68 × 1022 molecules of CBr4.

To calculate the mass of **8.68 × 10²² molecules of CBr₄** (carbon tetrabromide), we can follow these steps:

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### Step-by-Step Solution

1. **Find the molar mass of CBr₄:**
   - Carbon (C) = 12.01 g/mol  
   - Bromine (Br) = 79.90 g/mol  
   Since there are 4 bromine atoms,  
   \[ \text{Molar mass of CBr₄} = 12.01 + (4 \times 79.90) \]  
   \[ \text{Molar mass of CBr₄} = 12.01 + 319.60 = 331.61 \, \text{g/mol} \]  

2. **Use Avogadro’s number to find the number of moles:**
   - Avogadro’s number is \( 6.022 \times 10^{23} \) molecules per mole.  
   - The number of moles \( n \) is given by:  
     \[ n = \frac{\text{Number of molecules}}{6.022 \times 10^{23}} \]  
     \[ n = \frac{8.68 \times 10^{22}}{6.022 \times 10^{23}} \]  
     \[ n \approx 0.144 \, \text{mol} \]  

3. **Calculate the mass using the molar mass:**
   - Mass \( m \) = Moles \( n \) × Molar mass of CBr₄  
     \[ m = 0.144 \, \text{mol} \times 331.61 \, \text{g/mol} \]  
     \[ m \approx 47.76 \, \text{g} \]  

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### Final Answer
The mass of **8.68 × 10²² molecules of CBr₄** is approximately **47.76 grams**.

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Do you have any questions or need further details?  
Here are 5 related questions to explore further:  
1. How would the mass change if the molecule were CCl₄ instead of CBr₄?  
2. What is the concept of molar mass, and how does it relate to molecular weight?  
3. How many moles are in 1 gram of CBr₄?  
4. Can you express the mass in kilograms?  
5. What are the uses of carbon tetrabromide (CBr₄) in chemistry?

**Tip:** Always check unit consistency when dealing with large numbers, such as molecules or moles.

Calculate the mass in grams of 8.68 × 10²² molecules of CBr₄.

Learn how to calculate the mass of 8.68 × 10²² molecules of carbon tetrabromide (CBr₄) using molar mass and Avogadro's number. This guide provides a detailed solution, covering concepts like molar mass calculation and mole-to-mass conversion. Suitable for students in Grades 10-12.

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